Update 2022-02-08 17:21
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@@ -1,7 +1,7 @@
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<!DOCTYPE html>
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<html lang="en">
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<head>
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<!-- 2022-02-08 Tue 06:55 -->
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<!-- 2022-02-08 Tue 17:21 -->
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<meta charset="utf-8">
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<meta name="viewport" content="width=device-width, initial-scale=1">
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<title>Pre-Quantum Electrodynamics</title>
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@@ -272,6 +272,10 @@ Table of contents
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</summary>
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<ul>
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<li>
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<a href="./in_t_l.html#in_t_l">Section and equation labelling</a><span class="headline-id">in.t.l</span>
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</li>
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<li>
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<a href="./in_t_c.html#in_t_c">Contextual colors</a><span class="headline-id">in.t.c</span>
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</li>
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@@ -736,7 +740,7 @@ Table of contents
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</li>
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<li>
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<a href="./emsm_esm_d.html#emsm_esm_d">Dielectrics</a><span class="headline-id">emsm.esm.d</span>
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<a href="./emsm_esm_di.html#emsm_esm_di">Dielectrics</a><span class="headline-id">emsm.esm.di</span>
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</li>
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<li>
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@@ -1646,7 +1650,7 @@ we get
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But \({\bf J}\) depends only on \({\bf r}'\) so \({\boldsymbol \nabla} \times {\bf J} ({\bf r}') = 0\), and since
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the curl of a gradient always vanishes, we obtain
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</p>
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<div class="core div" id="orgdf5fc3e">
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<div class="core div" id="org8f6dda2">
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<p>
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\[
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{\boldsymbol \nabla} \cdot {\bf B} = 0
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@@ -1714,7 +1718,7 @@ at infinity), and in the third step we have used the assumption of steady-state
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<p>
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We thus obtain in total
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</p>
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<div class="core div" id="org3da2f25">
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<div class="core div" id="orga0245b5">
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<p>
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<b>Ampère's law</b>
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\[
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@@ -1731,7 +1735,7 @@ We thus obtain in total
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\]
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so
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</p>
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<div class="core div" id="org5aa5f70">
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<div class="core div" id="orgdbc9d47">
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<p>
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\[
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\oint_{\cal P} {\bf B} \cdot d{\bf l} = \mu_0 I_{enc} \hspace{2cm}
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@@ -1753,7 +1757,7 @@ Sign ambiguity: resolved by right-hand rule as usual.
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Ampère's law in magnetostatics takes a parallel role to Gauss's law in electrostatics.
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</p>
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<div class="example div" id="orgc846872">
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<div class="example div" id="orge2cd1ba">
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<p>
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\paragraph{Example 5.7:} same as Example 5.5, but now with Ampère.
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\paragraph{Solution:} by symmetry, \({\bf B}\) is circumferential and can only depend on \(s\). Then,
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@@ -1765,7 +1769,7 @@ choosing an amperian loop at a fixed radius \(s\), we get
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</div>
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<div class="example div" id="org1c375de">
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<div class="example div" id="orgf268569">
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<p>
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\paragraph{Example 5.8:} uniform surface current \({\bf K} = K \hat{\bf x}\) flowing in \(xy\) plane.
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\paragraph{Solution:} Biot-Savart: \({\bf B}\) must be perpendicular to \({\bf K}\). Intuition:
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@@ -1782,7 +1786,7 @@ and along \(\hat{\bf y}\) for \(z < 0\). Amperian loop of width \(l\) punchi
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</div>
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<div class="example div" id="orgc3e6b98">
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<div class="example div" id="org5e0a2eb">
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<p>
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\paragraph{Example 5.9:} solenoid along \(\hat{\bf z}\), wire carrying current \(I\) doing \(n\) turns per unit length on cylinder of radius \(R\).
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\paragraph{Solution:} by symmetry, \({\bf B}\) must be along axis of solenoid. Outside: infinitely far away, \({\bf B}\) must vanish.
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@@ -1803,7 +1807,7 @@ Amperian loop of length \(l\), half-inside and half-outside:
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i) infinite straight lines, ii) infinite planes, iii) infinite solenoids, iv) toroids.
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</p>
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<div class="example div" id="orgb302b1e">
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<div class="example div" id="org2a86e5f">
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<p>
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\paragraph{Example 5.10:} toroidal coil (no matter the shape, as long as it is rotationally symmetric).
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\paragraph{Solution:} magnetic field is circumferential everywhere. Outside coil, field again zero.
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@@ -1823,7 +1827,7 @@ Amperian loop half inside, half outside:
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<hr><div id="postamble" class="status">
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<p class="author">Author: Jean-Sébastien Caux</p>
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<p class="date">Created: 2022-02-08 Tue 06:55</p>
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<p class="date">Created: 2022-02-08 Tue 17:21</p>
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<p class="validation"><a href="https://validator.w3.org/check?uri=referer">Validate</a></p>
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</div>
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