Update 2022-02-14 06:33

This commit is contained in:
Jean-Sébastien
2022-02-14 06:33:37 +01:00
parent f8446c1405
commit 4cfe8cef59
204 changed files with 1839 additions and 941 deletions
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@@ -1,7 +1,7 @@
<!DOCTYPE html>
<html lang="en">
<head>
<!-- 2022-02-10 Thu 08:32 -->
<!-- 2022-02-13 Sun 21:20 -->
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>Pre-Quantum Electrodynamics</title>
@@ -1625,7 +1625,7 @@ we get
But \({\bf J}\) depends only on \({\bf r}'\) so \({\boldsymbol \nabla} \times {\bf J} ({\bf r}') = 0\), and since
the curl of a gradient always vanishes, we obtain
</p>
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<div class="core div" id="org18a16cf">
<p>
\[
{\boldsymbol \nabla} \cdot {\bf B} = 0
@@ -1667,7 +1667,7 @@ Last term:
= -{\bf J} ({\bf r}') \left({\boldsymbol \nabla}^2 \frac{1}{|{\bf r} - {\bf r}'|}\right) = -{\bf J} ({\bf r}') \left(-4\pi \delta^{(3)} ({\bf r} - {\bf r}') \right)
\label{Gr(5.51)}
\]
where we have used \ref{Gr(1.102)}. This term thus integrates to
where we have used <a href="./c_m_dd_3d.html#Lap1or">Lap1or</a>. This term thus integrates to
\[
\frac{\mu_0}{4\pi} \int_{\cal V} d\tau' {\bf J} ({\bf r}') 4\pi \delta^{(3)} ({\bf r} - {\bf r}') = \mu_0 {\bf J}({\bf r}).
\]
@@ -1693,7 +1693,7 @@ at infinity), and in the third step we have used the assumption of steady-state
<p>
We thus obtain in total
</p>
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<div class="core div" id="org8a17542">
<p>
<b>Ampère's law</b>
\[
@@ -1710,7 +1710,7 @@ We thus obtain in total
\]
so
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<p>
\[
\oint_{\cal P} {\bf B} \cdot d{\bf l} = \mu_0 I_{enc} \hspace{2cm}
@@ -1732,7 +1732,7 @@ Sign ambiguity: resolved by right-hand rule as usual.
Ampère's law in magnetostatics takes a parallel role to Gauss's law in electrostatics.
</p>
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<div class="example div" id="orgf88e8b6">
<p>
\paragraph{Example 5.7:} same as Example 5.5, but now with Ampère.
\paragraph{Solution:} by symmetry, \({\bf B}\) is circumferential and can only depend on \(s\). Then,
@@ -1744,7 +1744,7 @@ choosing an amperian loop at a fixed radius \(s\), we get
</div>
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<div class="example div" id="org0baadc2">
<p>
\paragraph{Example 5.8:} uniform surface current \({\bf K} = K \hat{\bf x}\) flowing in \(xy\) plane.
\paragraph{Solution:} Biot-Savart: \({\bf B}\) must be perpendicular to \({\bf K}\). Intuition:
@@ -1761,7 +1761,7 @@ and along \(\hat{\bf y}\) for \(z &lt; 0\). Amperian loop of width \(l\) punchi
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<p>
\paragraph{Example 5.9:} solenoid along \(\hat{\bf z}\), wire carrying current \(I\) doing \(n\) turns per unit length on cylinder of radius \(R\).
\paragraph{Solution:} by symmetry, \({\bf B}\) must be along axis of solenoid. Outside: infinitely far away, \({\bf B}\) must vanish.
@@ -1782,7 +1782,7 @@ Amperian loop of length \(l\), half-inside and half-outside:
i) infinite straight lines, ii) infinite planes, iii) infinite solenoids, iv) toroids.
</p>
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<div class="example div" id="orgea6064c">
<p>
\paragraph{Example 5.10:} toroidal coil (no matter the shape, as long as it is rotationally symmetric).
\paragraph{Solution:} magnetic field is circumferential everywhere. Outside coil, field again zero.
@@ -1800,6 +1800,8 @@ Amperian loop half inside, half outside:
</div>
<br><ul class="navigation-links"><li>Prev:&nbsp;<a href="ems_ms_dcB_sc.html">Straight-line Currents&emsp;<small>[ems.ms.dcB.sc]</small></a></li><li>Next:&nbsp;<a href="ems_ms_vp.html">The Vector Potential&emsp;<small>[ems.ms.vp]</small></a></li><li>Up:&nbsp;<a href="ems_ms_dcB.html">Divergence and Curl of \({\bf B}\)&emsp;<small>[ems.ms.dcB]</small></a></li></ul>
<br>
<hr>
<div class="license">
<a rel="license noopener" href="https://creativecommons.org/licenses/by/4.0/"
@@ -1813,7 +1815,7 @@ target="_blank">Creative Commons Attribution 4.0 International License</a>.
</div>
<div id="postamble" class="status">
<p class="author">Author: Jean-Sébastien Caux</p>
<p class="date">Created: 2022-02-10 Thu 08:32</p>
<p class="date">Created: 2022-02-13 Sun 21:20</p>
<p class="validation"></p>
</div>